c)
For a given gas the coefficient of viscosity is 1.9 x 10 Nsm and the diffusion
coefficient is 1.2 x 10-5 m?s-. Calculate the density and mean free path at average
molecular velocity of 380 ms-1
ρ=ηD=1.9⋅10−51.2⋅10−5=1.58 kgm3,\rho=\frac{\eta}{D}=\frac{1.9\cdot 10^{-5}}{1.2\cdot 10^{-5}}=1.58~\frac{kg}{m^3},ρ=Dη=1.2⋅10−51.9⋅10−5=1.58 m3kg,
λ=3Dv=3⋅1.2⋅10−5380=94.7 nm.\lambda=\frac{3D}{v}=\frac{3\cdot 1.2\cdot 10^{-5}}{380}=94.7~nm.λ=v3D=3803⋅1.2⋅10−5=94.7 nm.
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