Answer to Question #183674 in Molecular Physics | Thermodynamics for isacc chavez

Question

If we put a 12 kg piece of Gold with a temperature of 125 degrees Celsius into a bucket of water with a mass of 8 kg and a temperature of 2 degrees Celsius. What would the final temperature be? *

Answer 1

Solution.

$m_g=12kg;$

$T_g=125^oC;$

$c_g=125J/(kgK);$

$m_w=8kg;$

$t_w=2^oC;$

$c_w=4200J/(kgK);$

$T_f-?;$

$c_gm_g(T_g-T_f)=c_wm_w(T_f-T_w);$

$T_f=\dfrac{c_gm_gT_g+c_wm_wT_w}{c_gm_g+c_wm_w};$

$T_f=\dfrac{125J/(kgK)\sdot12kg\sdot125^oC+4200J/(kgK)\sdot8kg\sdot2^oC}{125J/(kgK)\sdot12kg+4200J/(kgK)\sdot8kg}=7^oC;$

Answer: $T_f=7^oC.$