Question #180757

Determine the mass and specific volume of argon gas in a vessel at 150 kPa and 20°C vessel is spherical and has a radius of 5m.


1
Expert's answer
2021-04-18T19:32:05-0400

The volume of the sphere is

V=43πr3\displaystyle V= \frac{4}{3} \pi r^3

P=150103  Pa,    T=293KP =150 \cdot 10^3 \; Pa, \; \; T=293 K

Using the ideal gas equation,

PV=nRT=mMRT\displaystyle PV = nRT = \frac{m}{M} RT


1) mass

m=PVMRT=1501031.3333.1453401038.31293=1289.9  kg1290  kg\displaystyle m = \frac{PVM}{RT} = \frac{150\cdot 10^3 \cdot 1.333 \cdot 3.14 \cdot 5^3 \cdot 40 \cdot 10^{-3}}{8.31 \cdot 293}= 1289.9 \; kg \approx 1290 \;kg

2) specific volume

v=Vm=1.3333.14531290=0.405  m3/kg\displaystyle v = \frac{V}{m} = \frac{1.333 \cdot 3.14 \cdot 5^3}{1290} =0.405 \; m^3/kg


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