Determine the mass and specific volume of argon gas in a vessel at 150 kPa and 20°C vessel is spherical and has a radius of 5m.
The volume of the sphere is
V=43πr3\displaystyle V= \frac{4}{3} \pi r^3V=34πr3
P=150⋅103 Pa, T=293KP =150 \cdot 10^3 \; Pa, \; \; T=293 KP=150⋅103Pa,T=293K
Using the ideal gas equation,
PV=nRT=mMRT\displaystyle PV = nRT = \frac{m}{M} RTPV=nRT=MmRT
1) mass
m=PVMRT=150⋅103⋅1.333⋅3.14⋅53⋅40⋅10−38.31⋅293=1289.9 kg≈1290 kg\displaystyle m = \frac{PVM}{RT} = \frac{150\cdot 10^3 \cdot 1.333 \cdot 3.14 \cdot 5^3 \cdot 40 \cdot 10^{-3}}{8.31 \cdot 293}= 1289.9 \; kg \approx 1290 \;kgm=RTPVM=8.31⋅293150⋅103⋅1.333⋅3.14⋅53⋅40⋅10−3=1289.9kg≈1290kg
2) specific volume
v=Vm=1.333⋅3.14⋅531290=0.405 m3/kg\displaystyle v = \frac{V}{m} = \frac{1.333 \cdot 3.14 \cdot 5^3}{1290} =0.405 \; m^3/kgv=mV=12901.333⋅3.14⋅53=0.405m3/kg
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