Question #175840

Mark sees a crushed soda can on the ground. He kicks it fiercely with a velocity of 12m/s at projected angle of 36°. What is the highest point that the soda can reaches? Sin 36 degrees equals 0.866. 2. A 5000 kg. freight train traveling at speed of 28 m/s strikes an identical car at rest. If they stick


1
Expert's answer
2021-03-29T09:03:07-0400

Solution.

1.v0=12ms1;1. v_0=12ms^{-1};

α=36o;\alpha =36^o;

hmax?;h_{max}-?;

v=0ms1;v=0ms^{-1};

v0y=v0sinα;v_{0y}=v_0\sdot sin \alpha; v0y=12ms10.866=10.392ms1;v_{0y}=12ms^{-1}\sdot0.866=10.392ms^{-1};

hmax=vy2v0y22g;h_{max}=\dfrac{v_y^2-v_{0y}^2}{2g};

hmax=0m2s2108m2s229.8ms2=5.51mh_{max}=\dfrac{0m^2s^{-2}-108m^2s^{-2}}{-2\sdot9.8ms^{-2}}=5.51m ;

2.m=5000kg;2. m=5000kg;

v1=28ms1;v_1=28ms^{-1};

v2=0ms1;v_2=0ms^{-1};

m1=m2=m;m_1=m_2=m;

mv1+mv2=(m1+m2)vFmv_1+mv_2=(m_1+m_2)v_F ;

vF=mv1+mv2m1+m2;v_F=\dfrac{mv_1+mv_2}{m_1+m_2};

vF=5000kg28ms1+5000kg0ms15000kg+5000kg=14ms1;v_F=\dfrac{5000kg\sdot28ms^{-1}+5000kg\sdot0ms^{-1}}{5000kg+5000kg}=14ms^{-1};

Answer: 1.hmax=5.51m;2.vF=14ms1.1. h_{max}=5.51m; 2. v_F=14ms^{-1}.





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