Answer to Question #172611 in Molecular Physics | Thermodynamics for Joeriem Mark

Question

a sample of gas held in 2.7m3 at a pressure of 226kPa. The temperature is kept constant while the pressure is increased to 484kPa. Calculate the the new volume of the gas.

Answer 1

$P_1 = 226kPa\\ V_1 = 2.7m³\\ P_2 = 484kPa\\ V_2 = \ ?$

from Boyle's law,

${P_1V_1} = {P_2V_2}$

226 × 2.7 = 484 × V₂

$V_2 = \dfrac{226 × 2.7 }{ 484}$

V₂ = 1.26m³

The new volume of the gas is 1.26m³.