Question

Define stagnation temperature. Air leaves the compressor of a jet engine at a temperature of

150°C, a pressure of 5 bar and a velocity of 120m/s. Determine the isentropic stagnation

temperature and pressure. 

Answer 1

$T=T_0+\frac{v^2}{c},$

$T=150+\frac{120^2}{1005}=164°C.$

$p=p_0\cdot \frac{T}{T_0},$

$p=5\cdot \frac{164}{150}=5.5~bar.$