10 kg water falls through a distance of 854m and all the energy is effective in heating the water.To what temperature will the water be raised if it was initially at 20c?
mgh=cmΔt,mgh=cm\Delta t,mgh=cmΔt,
gh=c(t2−t1),gh=c(t_2-t_1),gh=c(t2−t1),
t2=t1+ghc,t_2=t_1+\frac{gh}{c},t2=t1+cgh,
t2=20+9.8⋅8544200=22°C.t_2=20+\frac{9.8\cdot 854}{4200}=22°C.t2=20+42009.8⋅854=22°C.
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