Answer to Question #170716 in Molecular Physics | Thermodynamics for kebron tefera

Question #170716

Consider four uniformly charged plates oriented normal to the x-axis as shown. The drawing scale exaggerates the size of the

lengths along x compared to sizes along y

and z. Let L=1.0m, d=1.0mm, Q1=3.0C,

Q2=-3.0C, Q3=8.0C, and Q4=-6.0C. The positions of the plates are at x1, x2, x3 and x4.

  1. a) Find the 2D charge density of each plate
  2. b) Findthenetelectricfieldinregion
  3. x2 <x<x3. 
1
Expert's answer
2021-03-10T17:14:50-0500

Plate area, "A=l \\times d = 1*10^{-3}= 10^{-3} m^2"


Charge density of first plate, "\\sigma_1=\\frac{q_1}{A}=\\frac{3}{10^{-3}}=3\\times 10^{-3} Cm^{-2}"

Charge density on second plate, "\\sigma_2=\\frac{q_2}{A}=\\frac{-3}{10^{-3}}=-3\\times 10^{-3} Cm^{-2}"


Charge density on third plate, "\\sigma_3=\\frac{q_3}{A}=\\frac{8}{10^{-3}}=8\\times 10^{-3} Cm^{-2}"


Charge density on fourth plate, "\\sigma_4=\\frac{q_4}{A}=\\frac{-6}{10^{-3}}=-6\\times 10^{-3} Cm{-2}"


Let separation between the plates is 1m.

Electric field is given by, "E =\\frac{\\sigma_1- \\sigma_2- \\sigma_3+ \\sigma_1 }{\\epsilon_0}=\\frac{(3-3-8+6)*10^{3}}{8.85*10^{-12}} = 0.226*10^{9} N\/C"



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