the volume of a gas at temperature -73°c and pressure 480mm hg is 1000 cm find the volume of the same gas at pressure 760mm of maccury and 127°c
T1=−73+273=200 KP1=480 mmHg=0.631 atmV1=1000 cm3=1 LT2=127+273=400 KP2=760 mmHg=1 atmP1×V1T1=P2×V2T2V2=P1×V1×T2T1×P2=0.631×1×400200×1=1.262 L=1262 cm3T_1 = -73 + 273 = 200 \;K \\ P_1 = 480 \;mmHg \\ = 0.631 \;atm V_1 = 1000 \;cm^3 = 1 \;L \\ T_2 = 127 + 273 = 400 \;K \\ P_2 = 760 \;mmHg = 1 \;atm \\ \frac{P_1 \times V_1}{T_1} = \frac{P_2 \times V_2}{T_2} \\ V_2 = \frac{P_1 \times V_1 \times T_2}{T_1 \times P_2} \\ = \frac{0.631 \times 1 \times 400}{200 \times 1} \\ = 1.262 \;L = 1262 \;cm^3T1=−73+273=200KP1=480mmHg=0.631atmV1=1000cm3=1LT2=127+273=400KP2=760mmHg=1atmT1P1×V1=T2P2×V2V2=T1×P2P1×V1×T2=200×10.631×1×400=1.262L=1262cm3
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