Answer to Question #165153 in Molecular Physics | Thermodynamics for Tomiwa Epebinu

Question

The surface pressure on the planet venus is 95 atm,how far below th surface of the ocean in earth do you need to be to experience the same pressure

Answer 1

$$P=P_{atm}+\rho gd,$$ $$P-P_{atm}=\rho gd,$$ $$d=\dfrac{P-P_{atm}}{\rho g},$$ $$d=\dfrac{(95\ atm-1\ atm)\cdot\dfrac{1.013\cdot10^5\ Pa}{1\ atm}}{1025\ \dfrac{kg}{m^3}\cdot9.8\ \dfrac{m}{s^2}}=948\ m.$$