Question #165153

The surface pressure on the planet venus is 95 atm,how far below th surface of the ocean in earth do you need to be to experience the same pressure


Expert's answer

P=Patm+ρgd,P=P_{atm}+\rho gd,P−Patm=ρgd,P-P_{atm}=\rho gd,d=P−Patmρg,d=\dfrac{P-P_{atm}}{\rho g},d=(95 atm−1 atm)⋅1.013⋅105 Pa1 atm1025 kgm3⋅9.8 ms2=948 m.d=\dfrac{(95\ atm-1\ atm)\cdot\dfrac{1.013\cdot10^5\ Pa}{1\ atm}}{1025\ \dfrac{kg}{m^3}\cdot9.8\ \dfrac{m}{s^2}}=948\ m.
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