Question

What is the change in entropy in converting 1.0 kg of ice at 0.0-degree celsius to 1.0 kg water at 0.0 degrees celsius?

Answer 1

$\lambda=340~\frac{kJ}{kg},$

$\Delta S=\frac QT,$

$\Delta S=\frac{340\cdot 10^3\cdot 1}{273}=1245~\frac JK.$