Question #161867

If 5L of a gas is at 1.08 atm . Supposing the volume was 10L what will the volume be at a standard temperature


Expert's answer

p1V1=p2V2,p_1V_1=p_2V_2,

p2=p1V1V2,p_2=p_1\frac{V_1}{V_2},

p2=1.08⋅510=0.54 atm.p_2=1.08\cdot \frac{5}{10}=0.54~atm.


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