Answer to Question #161421 in Molecular Physics | Thermodynamics for Mary brown

Question

A ball is thrown down a building with an initial velocity of -5 m/s. It takes 6 seconds to reach the ground. How high is the building? What is the velocity when it hits the ground?

Answer 1

Initial velocity of the ball $u=5m/s$

Time taken by ball, $t=6s$

Final velocity is given by, $v=u+gt$

$v=5+(10*6)=65m/s$

It is the velocity with which ball will reach the ground