Question #161421

A ball is thrown down a building with an initial velocity of -5 m/s. It takes 6 seconds to reach the ground. How high is the building? What is the velocity when it hits the ground?


1
Expert's answer
2021-02-06T10:07:06-0500

Initial velocity of the ball u=5m/su=5m/s

Time taken by ball, t=6st=6s

Final velocity is given by, v=u+gtv=u+gt

v=5+(106)=65m/sv=5+(10*6)=65m/s

It is the velocity with which ball will reach the ground



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