Question #161362

What will be the change of temperature for 300 gr of iron (Fe) which have gained 2000 cal? (cFe= 0.11 cal/groC)


1
Expert's answer
2021-02-05T17:06:17-0500

Q=cFemΔt→Δt=QcFem=20000.11⋅300=60.6 (°C)Q=c_{Fe}m\Delta t\to\Delta t=\frac{Q}{c_{Fe}m}=\frac{2000}{0.11\cdot300}=60.6\ (°C) . Answer

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