What will be the change of temperature for 300 gr of iron (Fe) which have gained 2000 cal? (cFe= 0.11 cal/groC)
"Q=c_{Fe}m\\Delta t\\to\\Delta t=\\frac{Q}{c_{Fe}m}=\\frac{2000}{0.11\\cdot300}=60.6\\ (\u00b0C)" . Answer
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment