Question

What will be the change of temperature for 300 gr of iron (Fe) which have gained 2000 cal?

Answer 1

$$Q=mc\Delta T,$$ $$\Delta T=\dfrac{Q}{mc}=\dfrac{2000\ cal}{300\ g\cdot 0.107\ \dfrac{cal}{g \cdot^{\circ}C}}=62.3\ ^{\circ}C.$$