V1=0.50 m3P1=4.0 atmP2=1.0 atmT=constantP1V1=P2V2V2=P1×V1P2=0.5×4.01.0=2.0 m3V_1 = 0.50 \;m^3 \\ P_1 = 4.0 \;atm \\ P_2 = 1.0 \;atm \\ T = constant \\ P_1V_1 = P_2V_2 \\ V_2 = \frac{P_1 \times V_1}{P_2} \\ = \frac{0.5 \times 4.0}{1.0} \\ = 2.0 \;m^3V1=0.50m3P1=4.0atmP2=1.0atmT=constantP1V1=P2V2V2=P2P1×V1=1.00.5×4.0=2.0m3
Answer: 2.0 m3
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments