V=(4/3)πr3=(4/3)⋅3.14⋅0.33=0.113(m3)V=(4/3)\pi r^3=(4/3)\cdot3.14\cdot 0.3^3=0.113(m^3)V=(4/3)πr3=(4/3)⋅3.14⋅0.33=0.113(m3)
pV=νRT→pV=NNART→pV=\nu RT\to pV=\frac{N}{N_A} RT\topV=νRT→pV=NANRT→
N=pVNART=101325⋅0.113⋅6.02⋅10238.31⋅293.08=2.83⋅1024N=\frac{pVN_A}{RT}=\frac{101325\cdot 0.113\cdot 6.02\cdot10^{23}}{8.31\cdot 293.08}=2.83\cdot10^{24}N=RTpVNA=8.31⋅293.08101325⋅0.113⋅6.02⋅1023=2.83⋅1024 atoms. Answer
The average kinetic energy of motion of a helium molecule
Eavg=32kT=32⋅1.38⋅10−23⋅293.08=607⋅10−23 (J)E_{avg}=\frac{3}{2}kT=\frac{3}{2}\cdot 1.38\cdot 10^{-23}\cdot 293.08=607\cdot10^{-23}\ (J)Eavg=23kT=23⋅1.38⋅10−23⋅293.08=607⋅10−23 (J)
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