Answer to Question #160212 in Molecular Physics | Thermodynamics for Gill Allain

Question

An engine does 15.0kJ of work while exhausting 37.0kJ to a cold reservoir. What is the efficiency of the engine?

Answer 1

$Efficiency=\frac{Work done}{Exhausted}\times100$

$Efficiency=\frac{15}{37}\times100= 0.4054\times100=40.54$