Answer to Question #160212 in Molecular Physics | Thermodynamics for Gill Allain

Question #160212
An engine does 15.0kJ of work while exhausting 37.0kJ to a cold reservoir. What is the efficiency of the engine?
1
Expert's answer
2021-03-01T12:47:40-0500

"Efficiency=\\frac{Work done}{Exhausted}\\times100"


"Efficiency=\\frac{15}{37}\\times100= 0.4054\\times100=40.54"


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