Answer to Question #160200 in Molecular Physics | Thermodynamics for Harshita

Question

On a still -10°C day, an air film coats the inside of a single glazed glass (k= 0.84 Wm^-1 K ^-1) window. The window is 75 cm by 1m has 3mm thick glass . Assume h= 10. The inside temperature is 20°C . Find the rate of thermal energy flow .

Answer 1

Rate of flow of thermal energy is, $\frac{dQ}{dt }= \frac{KA\Delta T}{l}$

Where A is the area of the window,

K is the thermal conductivity,

l is the thickness of the window,

$\Delta T$ is the temperature difference.

$A = 0.75 \times 1 = 0.75 m^2$

$K = 0.84 Wm^{-1} K ^{-1}$

$\Delta T = 30^\circ C$ and $l = 3 mm = 3 \times 10^{-3}m$

Putting all the values, $\frac{dQ}{dt }= \frac{KA\Delta T}{l} = \frac{0.75 \times 0.84 \times 30}{3\times 10^{-3}} = 6.3 KJs^{-1}$