A hot water tank has 10cm of foam (k= 0.02 Wm^-1 K^-1) insulation surrounding the 60°C tank which is placed in 20°C room. The tank has surface area of 3.5 m^2 . Find the thermal energy lost over a one day period. This will equal the standby loss of tank. Ignore air films.
Rate of heat flow is given by "\\frac{dQ}{dt} = KA\\Delta T"
where K is thermal conductivity, A is the area, dt is the time, dQ is the heat and "\\Delta T" is the temperature difference.
Here we have, "K = 0.02, A = 3.5, \\Delta T = 60-20=40, t = 1day = 24*60*60=86400s"
Putting all values, Amount of heat flow is given by
"dQ = KA\\Delta T (dt) = 0.02 \\times 3.5\\times40\\times86400 = 241920 J = 241.92 KJ"
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