Vectors and are shown in the figure. Vector is given by = - . The magnitude of vector is 16.0 units, and the magnitude of vector is 7.00 units. What is the angle of vector , measured counterclockwise from the +x-axis?
Answer
Diagram can be written as
A→=−16sin42(i)+16cos42(j)\overrightarrow{A} = -16sin42(i) + 16cos42(j)A=−16sin42(i)+16cos42(j)
=-10.7(i) + 11.89(j)
B→=−7cos31(i)−7sin31(j)=−6(i)−3.6(j)\overrightarrow{B}= -7cos31(i) - 7sin31(j) \\=-6 (i) -3.6(j)B=−7cos31(i)−7sin31(j)=−6(i)−3.6(j)
v
vector c = vector b -vector a
4.7(i)-15.89(j)
θ=tan−1(15.89/4.7)=73.5°\theta=tan^{-1}(15.89/4.7)=73.5^°θ=tan−1(15.89/4.7)=73.5°
vector in 4 column of coordinate axis
angle will -73.5 degree
Means
286.47 degree
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