Explain rotational energy in term Of J.
In molecular physics and thermodynamics, one degree of freedom of rotational motion has energy 12kT\frac{1}{2}kT21kT . At room temperature (298 K)(298\ K)(298 K)
12kT≈12⋅1.38⋅10−23⋅298=206⋅10−23 ( J )\frac{1}{2}kT\approx\frac{1}{2}\cdot 1.38\cdot10^{-23}\cdot298=206\cdot10^{-23}\ (\ J\ )21kT≈21⋅1.38⋅10−23⋅298=206⋅10−23 ( J ) .Answer
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