A tyre of mass 15kg is suspended on a rope of length 7.5m and a girl of mass 75kg sits in the tyre. If the girls speed at the lowest point as she swings is 5m/s and the rope extends by 20cm, find the radius of this rope(young modulus = 2.0 x 10^11 Pa)
1
Expert's answer
2021-02-02T09:32:23-0500
Answer
radius of rope is given by
"r=\\sqrt{\\frac{mgl}{\\pi \\Delta l Y}}\\\\=\\sqrt{\\frac{(15+75)\\times10\\times7.5}{3.14\\times0.2\\times 2.0 \\times 10^{11} }}\\\\=231 \\times10^{-6}m"
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
Finding a professional expert in "partial differential equations" in the advanced level is difficult.
You can find this expert in "Assignmentexpert.com" with confidence.
Exceptional experts! I appreciate your help. God bless you!
Comments
Leave a comment