Q=kTln(W)
where k is constant =1.38×10= 1.38\times10=1.38×10-23
So heat = Q=(1.38×10Q = (1.38\times10Q=(1.38×10-23)×298×ln106)\times298\times ln 10^6)×298×ln106
Q=5.68×10Q = 5.68\times10Q=5.68×10-20 J
=0.3544eV= 0.3544 eV=0.3544eV
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