Question

The average depth of the Pacific Ocean is 4300 meters. What is the pressure of the water at this depth? (Ignore the air pressure on the ocean's surface.)

Answer 1

Pressure is

$$p = \rho g h$$

where $\rho$ is water density, $h$ is depth and $g = 9.8\,m/s^2$.

So we find

$$p = 1000\,kg/m^3 \cdot 4300\,m \cdot 9.8\,m/s^2 = 42140000\,Pa = 42.14\,MPa$$