Temperature is given by
T=13πr2σtmc3+1(Ts−Tsur)3+TsurT=\frac{1}{\sqrt[3]{\frac{3\pi r^2 \sigma t}{mc}}+\frac{1}{(T_s-T_{sur}) ^3}}+T_{sur}T=3mc3πr2σt+(Ts−Tsur)311+Tsur
When t goes to infinite then
T=Tsur=273+10=283KT=T_{sur}=273+10=283KT=Tsur=273+10=283K
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment