Answer
Specific volume is given by
"V_m=V\/m=0.86\/1"
"V_m=0.86kg\/m^3"
Here pressure is
"p=2bar=2\\times10^5N\/m^2"
Internal energy is written as
"E=3PV\/2=" "3\\times200000\\times0.86"
"E=258000J"
Enthalpy
H=U+PV=258+172=430000J
Entropy is given
S=U/T=258/423=0.61J/K
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