Answer
Specific volume is given by
Vm=V/m=0.86/1V_m=V/m=0.86/1Vm=V/m=0.86/1
Vm=0.86kg/m3V_m=0.86kg/m^3Vm=0.86kg/m3
Here pressure is
p=2bar=2×105N/m2p=2bar=2\times10^5N/m^2p=2bar=2×105N/m2
Internal energy is written as
E=3PV/2=E=3PV/2=E=3PV/2= 3×200000×0.863\times200000\times0.863×200000×0.86
E=258000JE=258000JE=258000J
Enthalpy
H=U+PV=258+172=430000J
Entropy is given
S=U/T=258/423=0.61J/K
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