"m_s = 0.05kg"
At 10 bar,
"\\begin{aligned}\ns_1 &= s_{f1} + x_1s_{fg1}\\\\\n&= 2.138 + 0.84(4.448)\\\\\n&= 5.874 kJ\/J.kg\n\\end{aligned}"
At 10 bar, "v_{g1}" = 0.1944m³/kg
"v_1 = x_1(v_{g1})"
"v_1 = 0.84\u00d70.1944" = 0.163m³/kg
"\\dfrac{V_1}{V_2} = (\\dfrac{P_1}{P_2})^{\\frac{1}{1.1}}"
"V_2 =" 0.163(10/20)¹.¹ = 0.163 × 0.533 = 0.087m³/kg
"x_2 = v_2\/v_{g2}" = 0.082/3.992 = 0.021
"s_2 = s_{f2} + x_2s_{fg2}"
= 1.026 + 0.021(6.646) = 1.166 kJ/kg.K
Change of entropy = "s_2 - s_1" = 1.166 - 5.874 = -4.708 kJ/kg.K
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