V1=150 sm3, V2=250 sm3, t1=100°C, t2=40°C,V_1=150 ~sm^3,~V_2=250 ~sm^3,~t_1=100°C,~t_2=40°C,V1=150 sm3, V2=250 sm3, t1=100°C, t2=40°C,
L=2.3⋅106 Jkg, c=4200 Jkg⋅°C,ρ1=0.6 kgm3, ρ2=1000 kgm3.L=2.3\cdot10^6~\frac{J}{kg},~c=4200~\frac{J}{kg\cdot °C}, \rho_1=0.6~\frac{kg}{m^3},~\rho_2=1000~\frac{kg}{m^3}.L=2.3⋅106 kgJ, c=4200 kg⋅°CJ,ρ1=0.6 m3kg, ρ2=1000 m3kg.
Q1=Lρ1V1=207 J.Q_1=L\rho_1V_1=207~J.Q1=Lρ1V1=207 J.
Q2=cρ2V2(t1−t2)=63000 J.Q_2=c\rho_2V_2(t_1-t_2)=63000~J.Q2=cρ2V2(t1−t2)=63000 J.
Q1≪Q2,Q_1\ll Q_2,Q1≪Q2, so full steam (150 sm3150 ~sm^3150 sm3) is condensed into water at 100°C.
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