Question

If 150cm3 of steam at 100∘C is added to 250cm3 water at 40∘C, how much steam(in cm3) is condensed into water at 100∘C?

Answer 1

Answer

Heat present in steam =m_sL

​=150×540cal

=81000cal

Heat required by water to raise temperature from 40^° to 100^°

=$m_s S\Delta T$

= 250×1×(100−40)

$=15000cal$

So

steam(in cm3) is condensed into water at 100∘C is

=250+$\frac{150\times5}{27}=277.77cm^3$