The moment of inertia of slim rod about a transverse axis through one
end is M(L^2)/3, where M is the mass of the rod and L its length, and L^2 is L
squared. What is the moment of inertia of the same rod if we choose a new
parallel axis at a distance of L/3 from the original axis?
1
Expert's answer
2020-12-04T09:34:52-0500
From the Huygens–Steiner theorem:
"J=J_C+Md^2,"
"J_C=\\frac{ML^2}{12},"
"d=\\frac L2 -\\frac L3=\\frac L6,"
so "J=\\frac{ML^2}{12}+\\frac{ML^2}{36}=\\frac{ML^2}{9}."
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