Question #147050
x^x + y^y = 3
x + y = 5

Find the value of x and y
1
Expert's answer
2020-11-27T10:16:00-0500

The question is actually

xx+yy=31x+y=5x^x + y^y = 31\\ x + y = 5

not,


xx+yy=3x+y=5x^x + y^y = 3\\ x + y = 5\\



The best way to solve this is graphically,

Table xx+yy=31x^x + y^y = 31\\

xy03.0413.042330x|y\\ 0|3.04\\ 1|3.04\\ 2|3\\ 3|0\\


Table x+y=5x + y = 5


xy05142332x|y\\ 0|5\\ 1|4\\ 2|3\\ 3|2\\




The points of intersection are (2,3) and (3,2)

\therefore x=2x=2 or 33

y=3y=3 or 22


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