Question #145945

For the Otto cycle of air shown, P1= 1 bar, T1 = 290 K, V1 = 400
cm3. If T3 = 2200 K and compression ratio is 8, find (a) the heat addition, in kJ, (b) the net work, in kJ, (c) the thermal efficiency.
The mass of the air is 0.48 g.

Expert's answer

(a)

Q1=νCV(T3T2)Q_1=\nu C_V(T_3-T_2)

γ=1.4\gamma=1.4

n=V1V2=8n=\frac{V_1}{V_2}=8

CV=Rγ1C_V=\frac{R}{\gamma-1}

ν=mM\nu=\frac mM

p2=p1(V1V2)γ=p1nγp_2=p_1(\frac{V_1}{V_2})^\gamma =p_1n^\gamma

T2=T1p2V2p1V1=T1nγn=T1nγ1=29080.4=666KT_2=T_1\cdot \frac{p_2V_2}{p_1V_1}=T_1 \cdot \frac{n^\gamma}{n}=T_1n^{\gamma-1}=290\cdot8^{0.4}=666 K

Q1=0.48298.310.4(2200666)=0.527kJQ_1=\frac{0.48}{29}\cdot \frac{8.31}{0.4}\cdot(2200-666)=0.527 kJ

(b)

Q2=νCV(T4T1)Q_2=\nu C_V(T_4-T_1)

p3=p2T3T2=p1nγT3T2p_3=p_2\frac{T_3}{T_2}=p_1n^\gamma\frac{T_3}{T_2}

p4=p3(V2V1)γ=p1nγT3T2nγ=p1T3T2p_4=p_3(\frac{V_2}{V_1})^\gamma=p_1n^\gamma\frac{T_3}{T_2}n^{-\gamma}=p_1\frac{T_3}{T_2}

T4=T3p4V4p3V3=T3p1T3T2p1nγT3T2n=T3n1γ=220080.4=958KT_4=T_3\frac{p_4V_4}{p_3V_3}=T_3\frac{p_1\frac{T_3}{T_2}}{p_1n^\gamma\frac{T_3}{T_2}}n=T_3n^{1-\gamma}=2200\cdot 8^{-0.4}=958 K

Q2=0.48298.310.4(958290)=0.230kJQ_2=\frac{0.48}{29}\cdot \frac{8.31}{0.4}\cdot(958-290)=0.230 kJ

(c)

η=11nγ1=1180.4=56\eta=1-\frac{1}{n^{\gamma-1}}=1-\frac{1}{8^{0.4}}=56 (%)


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