Question #145468
A Carnot engine 'X' operates between temperature T(1) and T(2) And (T(1)>T(2)). A second Carnot engine 'Y' uses all the heat rejected by the engine 'X' and operates between temperature T(2) and T(3)
( where T(2)>T(3)). The efficiency of this combined X and Y together engine is?
ANS:1- {[T(2)+T(3)]/T(1)}
1
Expert's answer
2020-11-23T05:28:08-0500

ηx=T1T2T1=1T2T1,\eta_x=\frac{T_1-T_2}{T_1}=1-\frac{T_2}{T_1},

ηy=(T1T2)T3T1T2=1T3T1T2,\eta_y=\frac{(T_1-T_2)-T_3}{T_1-T_2}=1-\frac{T_3}{T_1-T_2},

η=ηxηy=(1T2T1)(1T3T1T2)=T1T2T1T1T2T3T1T2=T1T2T3T1=1T2+T3T1.\eta=\eta_x\eta_y=(1-\frac{T_2}{T_1})\cdot(1-\frac{T_3}{T_1-T_2})=\frac{T_1-T_2}{T_1}\cdot\frac{T_1-T_2-T_3}{T_1-T_2}=\frac{T_1-T_2-T_3}{T_1}=1-\frac{T_2+T_3}{T_1}.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS