"\\textsf{Thermal Efficiency }(\\eta) = \\dfrac{W}{Q_H}"
(i) W = 5000J - 4500J = 500J
"Q_H" = 5000J
"\\eta = \\dfrac{500J}{5000J} = 0.1"
(ii) W = 2000J
"Q_H" = 25000J
"\\eta = \\dfrac{2000J}{25000J} = 0.08"
(iii) W = 400J
"Q_H" = 400J + 2800J = 3200J
"\\eta = \\dfrac{400J}{3200J} = 0.125"
"\\therefore" Engine number (iii) with 0.125 thermal efficiency has the highest efficiency, and Engine number (ii) with 0.08 thermal efficiency has the lowest efficiency.
Comments
Leave a comment