Question #144737

The volume of air at a pressure of 5 bar and at a temperature of 470o C is 0.5 m3. Calculate the mass of the air, and the gas constant. The universal gas constant is 8.315kJ/kg K.


1
Expert's answer
2020-11-24T05:42:26-0500
PV=nRTPV= nRT

also PV=massm.massRTPV= \frac{mass}{m.mass}\cdot RT

molar mass(air) = 0.029kg/mol

P= pressure= 5 Bar = 500000N/m2

V= volume = 0.5m3

T= Temperature= 470C = 470 + 273= 743K

R= universal gas constant= 8.315kJ/kg

500000×0.5=n×8.315×743500000\times0.5 = n\times 8.315\times743

nn = 500000×0.58.315×743\frac{500000\times0.5}{8.315\times743} mol

= 40.466mol


n=massmolar.massn=\frac{mass}{molar. mass}

40.466=mass0.029=\frac{mass}{0.029}

mass \approx 1.174Kg



Gas constant of air

Gasconstant=universalgasconstantm.massGas constant = \frac{universal \hspace{0.05cm}gas\hspace{0.05cm}constant}{m.mass}


gasconstant=8.3150.029gas\hspace{0.05cm}constant = \frac{8.315}{0.029}

gasconstant=287J/KgKgas constant = 287J/Kg\cdot K


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