i) Q1=5000J
Q2=4500J
η=1−Q1Q2=1−50004500=0.1
ii) Q1=25000J
W=2000J
W=Q1–Q2
Q2=25000–2000=23000J
η=1−Q1Q2=1−2500023000=0.08
iii) W=400J
Q2=2800J
W=Q1–Q2
Q1=W+Q2=400+2800=3200J
η=1−Q1Q2=1−32002800=0.125
Engine (iii) has the highest thermal efficiency 1.25.
Engine (ii) has the lowest thermal efficiency 0.08.
Comments
Thank you.