Initial velocity of truck is, u=26.8m/s
Retardation is, a=−4.91m/s2
Reaction time is 2 seconds
Distance covered in reaction time is, S1=26.8∗2=53.6m
Time taken by truck to come to rest, t=(v−u)/a=(0−26.8)/(−4.91)=5.5s
Distance covered in 5.5 seconds is, S2=ut−21at2=(26.8∗5.5)−(4.91∗5.5∗5.5/2)=73.14m
Total distance covered by truck is, S=S1+S2=53.6+73.14=126.74m
Then distance between truck and deer is D=140−126.74=13.26m
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