Initial velocity of truck is, "u=26.8 m\/s"
Retardation is, "a=-4.91m\/s^2"
Reaction time is 2 seconds
Distance covered in reaction time is, "S_1=26.8*2=53.6m"
Time taken by truck to come to rest, "t=(v-u) \/a=(0-26.8)\/(-4.91)=5.5s"
Distance covered in 5.5 seconds is, "S_2=ut-\\frac{1}{2}at^2=(26.8*5.5)-(4.91*5.5*5.5\/2)=73.14m"
Total distance covered by truck is, "S=S_1+S_2=53.6+73.14=126.74m"
Then distance between truck and deer is "D=140-126.74=13.26m"
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