Question #143605
For nitrogen the molar volume at s.t.p is 0.0024m³ and the relative molecular mass is 28. Calculate the number of molecules in one cm³ of nitrogen at s.t.p
1
Expert's answer
2020-11-10T06:58:51-0500

1cm3=1×106m30.0224m3=1 mole1×106m3=x mole1cm^3 = 1 × 10^{-6}m^3\\ \begin{aligned} \\ 0.0224m^3 &= 1\ mole\\ 1×10^{-6} m^3&= x\ mole \end{aligned}


x=1×1060.0224=4.464×105moles\begin{aligned} x&= \dfrac{1×10^{-6}}{0.0224} = 4.464×10^{-5}moles \end{aligned}



number of molecules=4.464×105moles×NA=4.464×105moles×6.02×1023molecules=2.69×1019molecules\begin{aligned} \textsf{number}&\textsf{ of molecules} = 4.464×10^{-5}moles × N_A\\ &=4.464×10^{-5}moles × 6.02× 10^{23} molecules\\ &= 2.69× 10^{19} molecules \end{aligned}

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Comments

Anthony Mwachughu
21.09.22, 21:52

Thanks good work

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