Question

Two liters of an ideal gas is collected at 25 °C and 745 mmhg. What is the volume at standard sea level conditions?

Answer 1

At standard sea level conditions the temperature is 15^oC, and the pressure is 760 mmHg.

25^oC = 298.15 K

15^oC = 288.15 K

According to the combined gas law,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}.$

Therefore,

$V_2=\frac{P_1V_1T_2}{T_1P_2}=\frac{745mmHg\times2.00L\times288.15K}{298.15K\times760mmHg}=1.89L$

Answer: 1.89 L