During the isothermal process the temperature remains constant, so Boyle's law is applicable:
P1V1=P2V2P_1V_1=P_2V_2P1V1=P2V2
V2=3V1=1.2L×3=3.6LV_2=3V_1=1.2L\times3=3.6LV2=3V1=1.2L×3=3.6L
Therefore, P2=P1V1V2=106dyn/cm2×1.2L3.6L=35.3dyn/cm2P_2=\frac{P_1V_1}{V_2}=\frac{106dyn/cm^2\times1.2L}{3.6L}=35.3dyn/cm^2P2=V2P1V1=3.6L106dyn/cm2×1.2L=35.3dyn/cm2
Answer: 35.3 dyn/cm2
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