Solution
For an isobaric process workdone
W = P(V2 - V1).
W=200000×(0.003−0.005)W=200000\times(0.003-0.005)W=200000×(0.003−0.005)
W=−400JW=-400JW=−400J
ΔQ=300J\Delta Q=300JΔQ=300J
Energy conservation: ΔU = ΔQ - ΔW.
ΔU = 300-(-400) =700J
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments