Question

A 100 kg mass drop 3 m, resulting in an increased volume in the cylinder of 0.002m^3. the weight and the piston maintain constant gage pressure of 100KPa. Determine the net work done by the gas on surroundings. Neglect all friction

Answer 1

As per the given question,

Word done by the drops $W_1=-F\times d =-100\times 9.8\times 3J$

$W_1=-2940J$

Work done by the system $W_2=PA\times h =100000\times 0.002J =200J$

Hence net required work done $W=-2940+200 =-2740J$