A 100 kg mass drop 3 m, resulting in an increased volume in the cylinder of 0.002m^3. the weight and the piston maintain constant gage pressure of 100KPa. Determine the net work done by the gas on surroundings. Neglect all friction
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Expert's answer
2020-11-09T06:51:09-0500
As per the given question,
Word done by the drops "W_1=-F\\times d =-100\\times 9.8\\times 3J"
"W_1=-2940J"
Work done by the system "W_2=PA\\times h =100000\\times 0.002J =200J"
Hence net required work done "W=-2940+200 =-2740J"
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