"Q_1 = 8\\times 30 \\times 2.1 = 504 \\;J" (from -8 °C to 0 °C)
"Q_2 = 75 \\times 30 \\times 4.2 = 9450 \\;J" (from 0 °C to 75 °C)
"Q_3 = 30 \\times 335 = 10050 \\;J" (heat of melting)
Total heat "Q_T = 504 + 9450 + 10050 = 20004 \\;J"
Answer: 20004 J
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