A lead block of mass 2kg falls from a height h to the ground. The specific heat capacity of lead is 120J/kgk and the rise in temperature is 0.4°C. Calculate the height
Answer
Change Potential energy = change in heat of leat
Mgh=MSΔTMgh=MS\Delta TMgh=MSΔT
h=SΔTgh=\frac{S\Delta T}{g}h=gSΔT
By putting the value
h=120×0.49.8=4.89mh=\frac{120\times0.4}{9.8}=4.89mh=9.8120×0.4=4.89m
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