Let 1 represent the first body and 2 represent the second body
u1=u2=u
θ1+θ2=90° (complementary angles)
∴θ2=90°−θ1
For body 1,
R1=gu12sin2θ1
R1=gu2sin2θ1
For body 2;
R2=gu22sin2θ2
R2=gu2sin2(90−θ1)
R2=gu2sin(180−2θ1)
sin(180−θ)=sinθThen, sin(180−2θ)=sin2θ
∴R2=gu2sin2θ1
R1=R2
∴ The range covered by two projectiles thrown up with the same initial velocities at angles of projection that are complementary is equal
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