Question #140246
What relation exist between the range covered by two projectiles thrown up with the same initial velocities at angles of projection that are complementary
1
Expert's answer
2020-10-29T07:37:10-0400

Let 1 represent the first body and 2 represent the second body


u1=u2=uu_1 = u_2 = u


θ1+θ2=90°\theta_1 + \theta_2 = 90° (complementary angles)

θ2=90°θ1\therefore \theta_2 = 90° - \theta_1


For body 1,


R1=u12sin2θ1gR_1 = \dfrac{{u_1}^2\, sin2\theta_1}{g}


R1=u2sin2θ1gR_1 = \dfrac{u^2\, sin2\theta_1}{g}


For body 2;


R2=u22sin2θ2gR_2 = \dfrac{{u_2}^2\, sin2\theta_2}{g}


R2=u2sin2(90θ1)gR_2 = \dfrac{{u}^2\, sin2(90-\theta_1)}{g}


R2=u2sin(1802θ1)gR_2 = \dfrac{{u}^2\, sin(180-2\theta_1)}{g}


sin(180θ)=sinθThen, sin(1802θ)=sin2θsin(180-\theta) = sin \theta\\ \textsf{Then, }sin(180 - 2\theta) = sin2\theta


R2=u2sin2θ1g\therefore R_2 = \dfrac{{u}^2\, sin2\theta_1}{g}


R1=R2R_1 = R_2


\therefore The range covered by two projectiles thrown up with the same initial velocities at angles of projection that are complementary is equal


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