Let 1 represent the first body and 2 represent the second body
"u_1 = u_2 = u"
"\\theta_1 + \\theta_2 = 90\u00b0" (complementary angles)
"\\therefore \\theta_2 = 90\u00b0 - \\theta_1"
For body 1,
"R_1 = \\dfrac{{u_1}^2\\, sin2\\theta_1}{g}"
"R_1 = \\dfrac{u^2\\, sin2\\theta_1}{g}"
For body 2;
"R_2 = \\dfrac{{u_2}^2\\, sin2\\theta_2}{g}"
"R_2 = \\dfrac{{u}^2\\, sin2(90-\\theta_1)}{g}"
"R_2 = \\dfrac{{u}^2\\, sin(180-2\\theta_1)}{g}"
"sin(180-\\theta) = sin \\theta\\\\\n\\textsf{Then, }sin(180 - 2\\theta) = sin2\\theta"
"\\therefore R_2 = \\dfrac{{u}^2\\, sin2\\theta_1}{g}"
"R_1 = R_2"
"\\therefore" The range covered by two projectiles thrown up with the same initial velocities at angles of projection that are complementary is equal
Comments
Leave a comment