As per the given question,
Ball is at the height (h)=3.7m
Initial speed of the ball (u)= 34 m/sec
time taken by the ball to reach on the ground "h=ut+\\frac{gt^2}{2}"
substituting the values,
"3.7= 34t +4.9t^2"
"4.9t^2+34t-3.7=0"
"t=\\frac{-34\\pm\\sqrt{34^2+4\\times 3.7\\times4.9}}{2\\times 4.9}=\\frac{-34\\pm 34.28}{9.8}"
Hence, "t=\\frac{0.28}{9.8}=0.28sec"
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