Answer to Question #133540 in Molecular Physics | Thermodynamics for Felicia McCarty

Question

One mole of a gas initially at 200C and 1 bar undergoes a cyclic process that brings it

back to its starting point. If the work is 338 J, find the heat involved in this process.

Answer 1

From 1st law of thermodynamics we know that:

$∆U = Q + W$

For a cyclic process the change in internal energy is zero i.e, $∆U =0$

$Q = -W = -338 \;J$

Answer: -338 J