Question #133540

One mole of a gas initially at 200C and 1 bar undergoes a cyclic process that brings it

back to its starting point. If the work is 338 J, find the heat involved in this process.



Expert's answer

From 1st law of thermodynamics we know that:

U=Q+W∆U = Q + W

For a cyclic process the change in internal energy is zero i.e, U=0∆U =0

Q=W=338  JQ = -W = -338 \;J

Answer: -338 J

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