Question #133540

One mole of a gas initially at 200C and 1 bar undergoes a cyclic process that brings it

back to its starting point. If the work is 338 J, find the heat involved in this process.



1
Expert's answer
2020-09-17T09:28:23-0400

From 1st law of thermodynamics we know that:

U=Q+W∆U = Q + W

For a cyclic process the change in internal energy is zero i.e, U=0∆U =0

Q=W=338  JQ = -W = -338 \;J

Answer: -338 J

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