Question #129752
Consider a gas sample of 12 g of oxygen (O_2) in a container, and it is heated at constant pressure, and when heated its temperature increases from 25⁰C to 125⁰C. (a) Calculate number of moles of oxygen present, (b) How much energy is transferred to oxygen gas as heat, keeping in mind that molecules rotate but do not vibrate. (c) What fraction of the heat is used to increase the internal energy of the oxygen?
1
Expert's answer
2020-08-18T11:09:37-0400

(а) n=m/M

n(O2)=12g/(32g/mol)=0.375moln(O_{2}) = 12 g / (32 g/mol) = 0.375 mol

(b) Molar specific heat of a diatomic gas (number of degrees of freedom = 5 [3 translation + 2 rotation], assuming molecules do not vibrate) at constant pressure Cp = \frac{7}{2}R

R is gas constant.

R=8.314J/KmolR = 8.314 J/Kmol

Cp(O2)=72×8.314=29.099J/KmolC_{p}(O_{2}) = \frac{7}{2}\times8.314 = 29.099 J/Kmol

ΔQ=n×Cp×ΔTΔQ=n\times C_{p}\timesΔT

ΔT = 100 K

ΔQ=0.375mol×29.099J/Kmol×100K=1091.21JΔQ=0.375 mol \times 29.099 J/Kmol \times 100 K = 1091.21 J  

ΔQ = 1.09 kJ

(c) Change in internal energy of O2O_{2} at constant volume:

ΔU=n×Cv×ΔTΔU=n\times C_{v}\timesΔT

Cv=52RC_{v}=\frac{5}{2}R

Ratio ΔU/ΔQ = (n×52\times\frac{5}{2} R×\times ΔT)/(n×72\times\frac{7}{2} R×\times ΔT) = 57\frac{5}{7}

57\frac{5}{7} fraction of heat supplied is used to increase the internal energy of the oxygen. 


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