Solution.
t1=20oC;t_1=20^oC;t1=20oC;
t2=0oC;t_2=0^oC;t2=0oC;
c=4200Jkg−1K−1;c=4200Jkg^{-1}K^{-1};c=4200Jkg−1K−1;
m=200g=0.2kg;m=200g=0.2kg;m=200g=0.2kg;
ΔW=cmΔt;\Delta W=cm\Delta t;ΔW=cmΔt;
ΔW=4200Jkg−1K−1⋅0.2kg⋅20K=16800J;\Delta W=4200Jkg^{-1}K^{-1}\sdot0.2kg\sdot20K=16800J;ΔW=4200Jkg−1K−1⋅0.2kg⋅20K=16800J;
Answer:ΔW=16800J.\Delta W=16800J.ΔW=16800J.
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